0=2cos^2x-(2sin^2x)

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Solution for 0=2cos^2x-(2sin^2x) equation:


Simplifying
0 = 2cos2x + -1(2sin2x)

Remove parenthesis around (2in2sx)
0 = 2cos2x + -1 * 2in2sx

Multiply -1 * 2
0 = 2cos2x + -2in2sx

Solving
0 = 2cos2x + -2in2sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2cos2x' to each side of the equation.
0 + -2cos2x = 2cos2x + -2cos2x + -2in2sx
Remove the zero:
-2cos2x = 2cos2x + -2cos2x + -2in2sx

Combine like terms: 2cos2x + -2cos2x = 0
-2cos2x = 0 + -2in2sx
-2cos2x = -2in2sx

Divide each side by '-2os2x'.
c = in2o-1s-1

Simplifying
c = in2o-1s-1

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